Math People

[Coopnasty]

How do I factor by grouping:

x^3 - x +5x^2 - 5

This shit blows, any help would be phenomenal.

[Charlie Hustles]

Math is for herbs. Drop the fuck out.

[taylor popham]

this is exactly why i haven't gone to college yet. i haven't taken a math class in 3 years and it's been so nice.

sorry i couldn't help ya though

[icr | phc]

You can't smoke weed and be good at math.

[Charlie Hustles]

When are you ever going to need to know that in real life?

[Coopnasty]

Math is for herbs. Drop the fuck out.

kthx

[Charlie Hustles]

For real, though, I used to be really good at math and I know that I knew how to do that, but after a good 6 years of never having to use it once, I forgot.

[blowakilo]

You can't smoke weed and be good at math.

thats not true, I have one friend who does smack, is an economist major and was awarded some second best scholar @ OSU WHILE having dope/water mixed in a nose spray bottle/doing it on stage.

another friend who is an electrical engineer and the most efficient math student I have ever seen.(forgot to add this) but he has smoked a shit load of pot since we were like 15, and does the smack occasionally as well.

now that I think about it, H is pretty big in this town. its the sux =(

you ever hear of those big professionals that get caught being opiate addicts(doctors, lawyers, etc) well, they all come from here

You have to be able to function in everyday life on drugs here in Oregon, there is just nothing else to do.

[BCarr4328]

How do I factor by grouping:

x^3 - x +5x^2 - 5

This shit blows, any help would be phenomenal.

x(x^2 - 1) + 5(x^2 - 1)

=

(x + 5) (x^2 - 1)

=

(x + 5) (x + 1) (x - 1)




Correct?

[Turnip Head]

X^2(x+5) + -1(x+5)

[Coopnasty]

How do I factor by grouping:

x^3 - x +5x^2 - 5

This shit blows, any help would be phenomenal.

x(x^2 - 1) + 5(x^2 - 1)

=

(x + 5) (x^2 - 1)

=

(x + 5) (x + 1) (x - 1)




Correct?

Actually you're correct, thank you!

[walterphelps]

You basically seperate the polynomial into two parts and pull out the greatest common factor. So you have....

X^3-X + 5x^2 - 5

Then do each seperately then combine

X(X^2-1) + 5(X^2-1)

Now the expression in the paretheses are the same so you can combine (I think it is the reverse of the distributive property)

(X+5)(X^2-1)

X^2-1 is a perfect square so the answer is...

(X+5)(X+1)(X-1)

[Turnip Head]

Fucking barr.

Fuck math, fuck factors by grouping, and fuck my google search.

[BCarr4328]

How do I factor by grouping:

x^3 - x +5x^2 - 5

This shit blows, any help would be phenomenal.

x(x^2 - 1) + 5(x^2 - 1)

=

(x + 5) (x^2 - 1)

=

(x + 5) (x + 1) (x - 1)




Correct?

Actually you're correct, thank you!

Dang Straight

[RobbedBlind]

x^3 - x + 5x^2 - 5

x (x^2 - 1) + 5 (x^2 - 1)

(x^2 - 1) (x + 5)

EDIT:
nm... got beat to the answer... and i guess i didnt factor it far enough

[BCarr4328]

x^3 - x + 5x^2 - 5

x (x^2 - 1) + 5 (x^2 - 1)

(x^2 - 1) (x + 5)

ok he obviously already got it.

i beat you all, Bitches

[Guest!mator]

ok, you need to put it in order first

x^3 + 5x^2 - x - 5

no you have an x^3, x^2 and x variable terms
the common denominator of these is x and x^2 so start there

(x^2.....)(x....)

look at what you're left with....

"+5x^2" shows you that the x^2 term must be mulltiplied in the parenthasis with the x....

while the "-5" must be multiplied by something... since we already have a 5 then it must leave -1 in the "x^2..." parenthesis.

(x^2 - 1)(x + 5)

[Charlie Hustles]

When are you ever going to need to know that in real life?

[BCarr4328]

When are you ever going to need to know that in real life?

Oh,at the grocery store of course.

[Guest!mator]

When are you ever going to need to know that in real life?

when dealing with a function that describes some sort of observable where the outcome is already known.

something that has an exponential growth which is determined by more than one term can be solved backwards to yield the rate of growth.

it's ironic that it's "exponentially" useful

it's simply a separation of terms, the same method would be used if the function contained more than one variable, this same method would be a sound way to extract physical data and used to make future predictions based off of previous observables(which dictated the actual function).